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The solubility of N2 gas in water at 25 ...

The solubility of `N_2` gas in water at `25 ""^(@)C` and 1 bar is `6.85 xx 10^(-4) mol L^-1` .Calculate (a) Henry's law constant (b) molarity of `N_2` gas dissolved in water under atmospheric conditions when partial pressure of `N_2` in atmosphere is 0.75 bar.

Text Solution

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a.`K_H=S/P=(6.85xx10^(-4)mol dm^(-3))/(1 "bar")`
`=6.85xx10^(-4)mol L^(-1)"bar"^(-1)`
b. `S=K_(H)P=6.85xx10(-4)molL^(-1)"bar"^(-1)xx0.75 "bar"`
`=5.138xx10^(-4)mol L^(-1)`
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