How many moles of electrons are required for reduction of 3 moles of `Zn^(2+)` to Zn? How many Faradays of electricity will be required ?

Explanation

i. The balanced equation for the reduction of `Zna^(2+)` Zn is
`Zn^(2+) (aq) + 2e^Theta to Zn(s)`
The equation shows that 1 mole of `Zn^(2+)` is reduced to Zn by 2 moles of electrons. For reduction of 3 moles of `Zn^(2+)` 6 moles of electrons will be required. Faraday (96500 Coulombs) is the amount of charge on one mole of electrons. Therefore, for 6 moles of electrons, 6 F electricity will be required.