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Calculate the voltage of the cell, Sn (s...

Calculate the voltage of the cell, `Sn (s) | Sn^(2+) (0.02M)| Ag^+ (0.01M) | Ag (s)` at `25^@C` .
`E_(Sn)^@ = -0.136V, E_(Ag)^@ = 0.800 V`.

Text Solution

Verified by Experts

First we write the cell reaction.

The cell potential is given by
`E_("Cell") = E_("Cell")^@ - (0.0592V)/(2) log_10 ([Sn^(2+)])/([Ag^+]^2)` `E_("Cell")^@ = E_(Ag)^@ - (0.0592V)/(2) log_10 ([Sn^(2+)])/([Ag^+]^2)`
`E_("Cell")^@ = E_(Ag)^@ - E_(Sn)^@ = 0.8V + 0.136V = 0.936V`
Hence, `E_("Cell") = 0.936V - (0.0592V)/(2) log_10 (0.02)/((0.01)^2)`
` = 0.936V - (0.0592V)/(2) log_10 200`
` = 0.936V - (0.0592V)/(2) xx 2.301`
` = 0.936V - 0.0681V = 0.8679V`
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