The normal at a point with parameter 2 on `y^2= 6x` again meets the parabola at point

The normal at a point P (36,36) on the parabola y^(2)=36x meets the parabola again at a point Q. Find the coordinates of Q.

The normal at a point t_1 on y^2 = 4ax meets the parabola again in the point t_2 . Then prove that t_1 t_2 + t_1^2 + 2=0

if the normal at the point t_(1) on the parabola y^(2) = 4ax meets the parabola again in the point t_(2) then prove that t_(2) = - ( t_(1) + 2/t_(1))

If the normal at (1,2) on the parabola y^(2)=4x meets the parabola again at the point (t^(2),2t) then the value of t is

If the normal at (1,2) on the parabola y^(2)=4x meets the parabola again at the point (t^(2),2t) then the value of t is

If the normal at(1, 2) on the parabola y^(2)=4x meets the parabola again at the point (t^(2), 2t) then the value of t, is

If the normal at(1, 2) on the parabola y^(2)=4x meets the parabola again at the point (t^(2), 2t) then the value of t, is

The normal at a point (bt_1^(2) , 2bt_1) on a parabola meets the parabola again in the point (bt_2^(2) , 2bt_2) then

The normal to the parabola y^(2)=8 x at the point (2,4) meets the parabola again at the point