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Look at the following pattern. i) 28=2^2...

Look at the following pattern. i) `28=2^2×7^1` , Total number of factors `(2+ 1) (1+1) = 3×2 = 6` 28 is divisible by 6 factors i.e., 1,2,4,7,14,28.

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The correct Answer is:
(i) The possible three conjucture are:
a) The product of any three consecutive odd number is odd.
b) The product of any three consecutive odd number is divisible by 3.
c) The sum of all the digits present in product of three consecutive odd numbers is even.
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