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Look at the following pattern. ii) 30=2^...

Look at the following pattern. ii) `30=2^1×3^1×5^1` , Total number of factors `(1+1)(1+1)(1+1)=2×2×2=8` 30 is divisible by 8 factors i.e., 1,2,3,5,6,10,15 and 30 Find the pattern. [Hint: product of every prime base exponent + 1)

Text Solution

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The correct Answer is:
The possible three conjuctures are:
a) The sum of any three consecutive number is always even.
b) The sum of any three consecutive number is always divided by 3.
c) The sum of any three consecutive number is always divided by 6
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