Solve the following riddle.
I am a number
Tell my identity.
Take me two times over
And add a thirty six.
To reach a century
You still need four.

Solve: I am a number, tell my identity, take me two times over and add a thirty six and to reach a century you still need four.

Solve the following : I am a number Tell my identity. Take seven times over and add a fifty to reach a triple century you still need forty.

Once again you are given four cards. Each card has a number printed on one side and a letter on the other side. Which are the only two cards you need to turn over to check whether the following rule holds? "If a card has a consonant on one side, then it has an odd number on the other side."

Estimating the following two numbers should be interesting. The first number will tell you why radio engineers do not need to worry much about photons! The second number tells you why our eye can never ‘count photons’, even in barely detectable light. (a) The number of photons emitted per second by a Medium wave transmitter of 10 kW power, emitting radiowaves of wavelength 500 m. (b) The number of photons entering the pupil of our eye per second corresponding to the minimum intensity of white light that we humans can perceive (~10^(-10) W m^(-2)) . Take the area of the pupil to be about 0.4 cm2 , and the average frequency of white light to be about 6 xx 10^(14) Hz

Let us do the following activity to understand the mendelian principles of heredity. Materaials required: a. 3cm length and 1 cm breadth chart pieces -4 b. 2 cm length and 1 cm breadth chart pieces -4 c. Red byuttons -4 d. white buttons -4 e. chart, scale, sketch pen penil, 2 bags. Method: Prepare a chart with 2x2 boxes along with numbe and symbol as shown in the figure. Game 1: Monohybrid cross (starting with hybrid parents) To start with take 1,2 or 3,4 . In case you start 1,2 pik all the 16 log and short pieces and prepare such paris in each of which you have a long and short piece. Take 4 pairs each of long and short strips and put them in two separate bags. Now each bag contains 8 strips (4 long and 4short). One bag say 'A' represents mael and the bag 'B' represents female . Now rendomly pick one strip each from bag A and B and put them together in the 1 on the chart. Keep picking out the strips and arrange them in the same manner till your bags are empty. Same time your boxes in the chart are filled with paris of strips. you might have got the following combinations, two long strips, one long and one short strip, two short strips. (Q) A. what is the number of long strip paris?

Let us do the following activity to understand the mendelian principles of heredity. Materaials required: a. 3cm length and 1 cm breadth chart pieces -4 b. 2 cm length and 1 cm breadth chart pieces -4 c. Red byuttons -4 d. white buttons -4 e. chart, scale, sketch pen penil, 2 bags. Method: Prepare a chart with 2x2 boxes along with numbe and symbol as shown in the figure. Game 1: Monohybrid cross (starting with hybrid parents) To start with take 1,2 or 3,4 . In case you start 1,2 pik all the 16 log and short pieces and prepare such paris in each of which you have a long and short piece. Take 4 pairs each of long and short strips and put them in two separate bags. Now each bag contains 8 strips (4 long and 4short). One bag say 'A' represents mael and the bag 'B' represents female . Now rendomly pick one strip each from bag A and B and put them together in the 1 on the chart. Keep picking out the strips and arrange them in the same manner till your bags are empty. Same time your boxes in the chart are filled with paris of strips. you might have got the following combinations, two long strips, one long and one short strip, two short strips. (Q) B. What is the number of one long and one short pairs?

Let us do the following activity to understand the mendelian principles of heredity. Materaials required: a. 3cm length and 1 cm breadth chart pieces -4 b. 2 cm length and 1 cm breadth chart pieces -4 c. Red byuttons -4 d. white buttons -4 e. chart, scale, sketch pen penil, 2 bags. Method: Prepare a chart with 2x2 boxes along with numbe and symbol as shown in the figure. Game 1: Monohybrid cross (starting with hybrid parents) To start with take 1,2 or 3,4 . In case you start 1,2 pik all the 16 log and short pieces and prepare such paris in each of which you have a long and short piece. Take 4 pairs each of long and short strips and put them in two separate bags. Now each bag contains 8 strips (4 long and 4short). One bag say 'A' represents mael and the bag 'B' represents female . Now rendomly pick one strip each from bag A and B and put them together in the 1 on the chart. Keep picking out the strips and arrange them in the same manner till your bags are empty. Same time your boxes in the chart are filled with paris of strips. you might have got the following combinations, two long strips, one long and one short strip, two short strips. (Q) C. What is the number of short strip pairs?