Home
Class 14
MATHS
In triangle ABC, angleC = 90^(@) and CD ...

In triangle ABC, `angleC = 90^(@)` and CD is the perpendicular from C to AB.
If `(CD)^(-2) = (BC)^(-2) + (CA)^(-2)`, then which one of the following is correct ?

A

BC.CD = AB. CA

B

AB.BC = CD.CA

C

`CA^(2) + CB^(2) = 2 (AD^(2) + CD^(2))`

D

AB.CD = BC.CA

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

In DeltaABC,angleC=90^(@) and CD is perpendicular to AB at D. If (AD)/(BD)=sqrtk , then (AC)/(BC)=?

In a right-angled triangle ABC, angleC = 90^(@) and CD is perpendicular to AB. If AB x CD = CA x CB, then 1/(CD^(2)) is equal to:

In a triangle ABC, angleBCA = 90^(@) and CD is perpendicular to AB. If AD = 4 cm and BD = 9 cm, then the value of DC will be

In a triangle ABC, AD is perpendicular on BC. If angle BAC = 90^(@), AB = c, BC = a, CA = b and AD = p, then which one of the following is correct?

ABC is a triangle right angled at C with BC = a and AC = b. If p is the length of the perpendicular from C on AB, then which one of the following is correct ?

In a right angled DeltaABC, angleC=90^(@) and CD is the perpendicular on hypotenuse AB if BC = 15 cm and AC = 20 cm then CD is equal to :

In a right triangle ABC, right angled at A, AD is drawn perpendicular to BC. Prove that: AB^(2)-BD^(2)= AC^(2)-CD^(2)

In Delta ABC, angle B = 90^(@) and d is the mid - point of BC. Prove that AC ^(2) = AD^(2) + 3CD ^(2)

In a triangle ABC,B=90^(@) and D is the mid-oint of BC then prove that AC^(2)=AD^(2)+3CD^(2)