If AB and CD are intersecting at ‘O’, OA = OB and OD = OC. Show that
`triangle AOD ~= triangle BOC `

In a Figure AB and CD are intersecting at ‘O’, OA = OB and OD = OC. Show that AD "||" BC .

In the given figure, AB "||"Dc and AD "||"BC Show that triangle ABC ~= triangle CDA

In the adjacent figure, triangle ABC and triangle DBC are on the same base BC. If AD and BC intersect at O, Prove that (area of triangle ABC )/(area of triangle DBC) = (AO) /(DO)

In the figure given below triangleABC and triangleDBC are two triangles such that AB=BD, and AC=CD. Show that triangleABC~=DBC

In an isosceles triangle ABC, with AB = AC, the bisectors of /_ B and /_ C intersect each other at O. Join A to O. Show that : (i) OB = OC (ii) AO bisects /_A

The diagonal of a trapezium ABCD in which AB////CD intersect at'O' . IF AB=2CD then the ratio of areas of triangles AOB and COD is……….

P, Q, R are the midpoints of the sides AB, BC and CA of the triangle ABC and O is a point within the triangle, then OA + OB + OC =

triangle ABC is right angled at C and CD bot AB, angle A = 55^(@) angle BCD=