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Al((s)) + fe(2)O(3(s)) to Al(2) O(3(s)) ...

`Al_((s)) + fe_(2)O_(3(s)) to Al_(2) O_(3(s)) + Fe_((s))`
(atomic masses of Al = 27U, Fe = 56U, and O = 16U)

`2Al_((s)) +Fe_(2)O_(3(s)) to Al_(2)O_(3(s)) + 2Fe_((s))` , is a balanced equation.
`(2 xx 27)U + (2xx 56 + 3xx 16)U to (2xx 27 + 3 xx 16) U + (2 xx 56) U`
`{:(54U+160U,,to102U+112U),(or2" mol" + "1 mol",,to 1"mol" + 2"mol"),(54g + 160g ,, to 102 g + 112 g):}`
Suppose that your asked to calculate the amount of aluminium, required to get 1120 kg of iron by the above reaction.

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