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(cos (pi +x ) cos (-x))/(sin(pi - x)cos...

`(cos (pi +x ) cos (-x))/(sin(pi - x)cos( pi/2 + x))` =

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Given,
L.H.S
`[cos(pi+x)cos(-x)]/[ sin(pi-x)cos(pi/2+x)]`
`=[ -(cosxcosx)]/[-(sinxsinx)]`
...
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