`1/2 int (dt)/(1 + t)`

(1)/(2)int(dt)/(t sqrt(t-1))

if int(e^(t)dt)/(1+t)=a then int e^(t)(dt)/((1+t)^(2))=

If int_(0) ^(x) f (t) dt = x + int _(x ) ^(1) t f (t) dt, then the value of f (1) , is

Given a function 'g' continous everywhere such that int _(0) ^(1) g (t ) dt =2 and g (1)=5. If f (x ) =1/2 int _(0) ^(x) (x-t) ^(2)g (t)dt, then the vlaue of f'(1)-f'(1) is:

int (-1)/(t-1) dt - int 1/t dt

" (a) "int(dt)/(sqrt(1-t^(2)))

2int_(0)^(t)(1-cos t)/(t)dt

[int_(1/e)^( tan x)(tdt)/(1+t^(2))+int_(1/e)^( cot x)(dt)/(t(1+t^(2)))" is "],[" equal to "]

Integrate the following : int(dt)/((6t-1))