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What is the simplified form of cos^(4)th...

What is the simplified form of `cos^(4)theta- sin^(4) theta` in terms of `sin theta`

A

`1-2 sin^2 theta`

B

`2 sin^(2) theta +1`

C

`sin^2 theta +1`

D

`sin^2 theta+2`

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The correct Answer is:
To simplify the expression \( \cos^4 \theta - \sin^4 \theta \) in terms of \( \sin \theta \), we can follow these steps: ### Step 1: Rewrite the expression Start with the expression: \[ \cos^4 \theta - \sin^4 \theta \] ### Step 2: Recognize the difference of squares Notice that this expression can be factored using the difference of squares formula: \[ a^2 - b^2 = (a + b)(a - b) \] Here, let \( a = \cos^2 \theta \) and \( b = \sin^2 \theta \). Thus, we can rewrite the expression as: \[ (\cos^2 \theta + \sin^2 \theta)(\cos^2 \theta - \sin^2 \theta) \] ### Step 3: Use the Pythagorean identity From the Pythagorean identity, we know: \[ \cos^2 \theta + \sin^2 \theta = 1 \] So, we can substitute this into our expression: \[ 1 \cdot (\cos^2 \theta - \sin^2 \theta) = \cos^2 \theta - \sin^2 \theta \] ### Step 4: Rewrite \( \cos^2 \theta \) in terms of \( \sin \theta \) We need to express \( \cos^2 \theta \) in terms of \( \sin \theta \). Using the identity \( \cos^2 \theta = 1 - \sin^2 \theta \), we substitute: \[ \cos^2 \theta - \sin^2 \theta = (1 - \sin^2 \theta) - \sin^2 \theta \] ### Step 5: Simplify the expression Now, simplify the expression: \[ 1 - \sin^2 \theta - \sin^2 \theta = 1 - 2\sin^2 \theta \] ### Final Answer Thus, the simplified form of \( \cos^4 \theta - \sin^4 \theta \) in terms of \( \sin \theta \) is: \[ \boxed{1 - 2\sin^2 \theta} \]
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