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There are 20 vehicles-cars and motor cyc...

There are 20 vehicles-cars and motor cycles in a parking area. If there are 56 wheels together, how many cars are there?

A

8

B

10

C

12

D

20

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find out how many cars are in the parking area given the total number of vehicles and wheels. Let's break it down step by step. ### Step 1: Define Variables Let: - \( x \) = number of cars - \( y \) = number of motorcycles ### Step 2: Set Up Equations From the problem, we know: 1. The total number of vehicles (cars and motorcycles) is 20: \[ x + y = 20 \quad \text{(Equation 1)} \] 2. The total number of wheels is 56. Since cars have 4 wheels and motorcycles have 2 wheels, we can express this as: \[ 4x + 2y = 56 \quad \text{(Equation 2)} \] ### Step 3: Solve Equation 1 for one variable From Equation 1, we can express \( y \) in terms of \( x \): \[ y = 20 - x \] ### Step 4: Substitute into Equation 2 Now, substitute \( y \) in Equation 2: \[ 4x + 2(20 - x) = 56 \] Expanding this gives: \[ 4x + 40 - 2x = 56 \] ### Step 5: Simplify the Equation Combine like terms: \[ 2x + 40 = 56 \] ### Step 6: Isolate \( x \) Subtract 40 from both sides: \[ 2x = 56 - 40 \] \[ 2x = 16 \] ### Step 7: Solve for \( x \) Divide both sides by 2: \[ x = \frac{16}{2} = 8 \] ### Step 8: Conclusion Thus, the number of cars \( x \) is 8.
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