`A=36%B,B=6%C`. If `C=100` then A is equal to
(A) 2.18
(B) 2.21
(C) 2.16
(D) 2.24

If log_(4)x+log_(2)x=6, then x is equal to a.2 b.4 c.8 d.16

5.36 xx 3.6 = (A) 19.296 (C) 21.996 (B) 18.946 (D) 20.26

6, 9, 15, 21, 24, 28, 30 (a) 28 (b) 21 (c) 24 (d) 30

A=[(1,2),(2,1)], then adjoint of A is equal to (A) [(1,-2),(-2,1)] (B) [(2,1),(2,1)] (C) [(1,-2),(-2,1)] (D) [(-1,2),(2,-1)]

If |(a,a^2,1+a^3),(b,b^2,1+b^3),(c,c^2,1+c^2)|=0 and vectors (1,a,a^2),(1,b,b^2) and (1,c,c^2) are hon coplanar then the product abc equals (A) 2 (B) -1 (C) 1 (D) 0

(-2)x\ (-3)x\ 6\ x\ (-1) is equal to (a)36 (b) -36 (c) 6 (d) -6

let 2..^(20)C_(0)+5.^(20)C_(1)+8.^(20)C_(2)+?.+62.^(20)C_(20) . Then sum of this series is (A) 16.2^(22) (B) 8.2^(21) (C) 8.2^(21) (D) 16.2^(21)

If |(a-b-c, 2a, 2a),(2b, b-a-c, 2b),(2c, 2c, c-a-b)|=(a+b+c)(x+a+b+c^2) then thhe value of x is equal to (A) -2(a+b+c) (B) a+b+c (C) -(a+b+c) (D) 2(a+b+c)

Find the value of sqrt(20^(2)-16^(2)) A)12 B)18 C)16 D)14

1, 1, 2, 6, 24, 96, 720 (a) 720 (b) 96 (c) 24 (d) 6 (e) 2