2.Simplify `1frac{3}{4}xx2frac{2}{5}xx3frac{4}{7}`

Simplify 7-(2frac(3)(4) + 2frac(1)(2))

Let (alpha, beta, gamma) be the foot of perpendicular from the point (1, 2, 3,) on the line frac{x 3}{5} = frac{y - 1}{2} = frac{z 4}{3} then 19 (alpha beta gamma)

Determine the term independent of a in the expansion of (frac{a+1}{a^frac{2}{3}-a^frac{1}{3}+1)-frac{a-1}{a-a^frac{1}{2}))^10

Simplify : (27)^frac(-2)(3)

Add the following: 3frac{1}{13} + 1frac{4}{13} + 2frac{3}{13}

Simplify: frac(7)(-27)+frac(11)(18).

. Simplify: (i) frac(-36)(7) xx frac(-14)(9) (ii) frac(-8)(13) xx frac(39)(-4)

((3frac{1}{3}-2frac{1}{2})div 1/4 of 1frac{1}{4})/(10+6 xx 3) of 4/15 div ((1/3div1/3 of 1/9)/(9 xx 3div6))

Solve - frac{sin^(3) frac{x}{2} -cos^(3) frac{x}{2}}{2 +sinx} = cosx/3