If tanalpha=m/(m+1)a n dtanbeta=1/(2m+1)...

If `tanalpha=m/(m+1)a n dtanbeta=1/(2m+1)` . Find the possible values of `(alpha+beta)`

A

`pi/3`

B

`pi/4`

C

zero

D

`pi/2`

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The correct Answer is:

B

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