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A uniform rod AB of length l and mass m ...

A uniform rod AB of length l and mass m is free to rotate about point A. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is `(ml^2)/3`, the initial angular acceleration of the rod will be

A

`(2g)/(3l)`

B

`mg l/2`

C

`3/2 gl`

D

`(3g)/(2l)`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • A uniform rod of lengthl and massm is free to rotate in a vertical plane about A. The rod initially in horizontal position is released. The initial angular acceleration of the rod is (Moment of inertia of rod about A is (ml^(2))/(3)

    A
    `(3g)/(2l)`
    B
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    C
    `(3g)/(2l^(2))`
    D
    `"mg"(l)/(2)`
  • A unifrom rod of length l and mass m is free to rotate in a vertical plane about A as shown in Fig. The rod initially in horizontal position is released. The initial angular acceleration of the rod is

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  • A unifrom rod of length l and mass m is free to rotate in a vertical plane about A , Fig. The rod initially in horizontal position is released. The initial angular acceleration of the rod is (MI "of rod about" A "is" (ml^(2))/(3))

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    `mgl//2`
    B
    `3 g//2l`
    C
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    D
    `3g//2l^(2)`
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