The bob of a pendulum of length l is pulled a side from its equilibrium position through an angle `theta` and then released the bob will then pass through its equilibrium position with a speed v where v equals to

Options

A. `sqrt(2g/(1-sin theta))`
B. `sqrt(2g/(1+cos theta))`
C. `sqrt(2g/(1-cos theta))`
D. `sqrt(2g/(1+sin theta))`

Answer

C