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For the reaction , X(s) harr Y(s) + Z(g)...

For the reaction , `X(s) harr Y(s) + Z(g)`, the plot of ln`(pz)/p^(theta)` versus `10^4/T` is given below (in solid line), where `p_z` is the pressure (in bar) of the gas at temperature T and `p^(theta)`= 1bar
( Given, `(d(lnK))/(d(1/T))= - (DeltaH^(theta))/R`, where the equilibrium constant , `K= p_z/p^(theta)` and the gas constant, R=8.314`JK^(-1)mol^(-1)`
The value of standard enthalpy,`DeltaH^(theta)`(in `kjmol^(-1)`) for the given reaction is ---------`

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For the reaction , X(s) harr Y(s) + Z(g) , the plot of ln (pz)/p^(theta) versus 10^4/T is given below (in solid line), where p_z is the pressure (in bar) of the gas at temperature T and p^(theta) = 1bar ( Given, (d(lnK))/(d(1/T))= - (DeltaH^(theta))/R , where the equilibrium constant , K= p_z/p^(theta) and the gas constant, R=8.314 JK^(-1)mol^(-1) The value of DeltaS^(theta) (in jmol^(-1) ) for the given reaction at 1000K is ---------

The equilibrium constant for a reaction is 100 what will be the value of DeltaG^(@) ? R=8.314JK^(-1)mol^(-1),T=300 K :-

The quantitative relationship between the vapor pressure p of a liquid and the absolute temperature T is given by the Clausius - Clapeyron equation, In_(p) = - (Delta_(vap)H)/(RT) + C where In is the natural logarithm , R is the gas constant (8.314 JK^(-1) mol^(-)) , and C is a constant . The plot of

The equilibrium constant for a reaction is 10 . What will be the value of DeltaG^(Θ) ? R=8.314 J K^(-1) mol^(-1), T=300 K .

If the equilibrium constant for a reaction is 10, then the value of triangleG^(@) will be: ("Given: "R= 8JK^(-1) mol^(-1) T=300K)

The standard free energy change of a reaction is DeltaG^(@)=-115 at 298K. Calculate the equilibrium constant K_(P) in log K_(P).(R=8.314JK^(-1)mol^(-1))

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