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The percentage of zinc in ZnSO(4).7H(2)O...

The percentage of zinc in `ZnSO_(4).7H_(2)O` is
(Zn = 65, S = 32, 0= 16, H = 1)

A

23

B

13

C

17

D

33

Text Solution

Verified by Experts

The correct Answer is:
B
Molecular wwight of `Zn SO _(4). 7 H _(2)O`
`65 + 32 + 4 xx 16 + 7 (2 xx 1 + 16)`
` = 65 + 32 + 64 + 126`
`= 287 g mol ^(-1)`
`therefore 287 g Zn SO _(4). 7 H _(2) O ` contains `Zn = 65 g`
`therefore 100 g Zn SO _(4). 7 H _(2) O` will contain `Z n = ( 65 xx 100)/(287) = 22. 65 ~~ 23 ~~ 23 %`
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