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The H—O—H bond in water molecule is:...

The H—O—H bond in water molecule is:

A

`104^(@) 31'`

B

`120^(@)`

C

`180^(@)`

D

`109^(@)28'`

Text Solution

Verified by Experts

The correct Answer is:
A
In water molecule, H—O—H bond angle is `104^(@) 31.` his bond angle is less than tetrahedral angle (`109^(@) 28.` due to greater lone pair-lone-pair repulsion.
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Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R: Assertion A: The H-O-H bond angle in water molecule is 104.5^(@) Reason R: The lone pair - lone pair repulsion of electrons is higher than the bond pair - bond pair repulsion. In the light of the above statements, choose the correct answer from the options given below:

The experimental dipole moment of water molecule is 1.84D . Calculater the bond angle H-O-H in water molecule if dispole moment of OH bond is 1.5D .

Knowledge Check

  • The H-O-H angle in water molecule is about

    A
    90°
    B
    180°
    C
    102°
    D
    105°

  • The H-O-H angle in water molecule is about

    A
    `90^(@)`
    B
    `180^(@)`
    C
    `102^(@)`
    D
    `105^(@)`

  • The H-O-H bond angle in water molecule is about:

    A
    `105^(@)`
    B
    `109^(@)`
    C
    `180^(@)`
    D
    `90^(@)`

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