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By passing SO2 in the solution of K2Cr2O...

By passing `SO_2` in the solution of `K_2Cr_2O_7`, it turns green due to

A

`K_(2)CrO_(4)`

B

`CrSO_(4)`

C

`Cr_(2)(SO_(4))_(3)`

D

`Cr_(2)S_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
Acidic `K_2Cr_2O_7` turns.green by passing `SO_2` gas.
`3SO_(2) + K_(2)Cr_(2)O_(7) + H_(2)SO_(4) to K_(2)SO_(4) + underset("Green")(Cr_(2)(SO_(4))_(3)) H_(2)O`
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