A solution of `SO_2` in water reacts with `H_2S` precipitating sulphur. Here `H_2S` acts as:

Options

A. an oxidising agent
B. a reducing agent
C. an acid
D. a catalyst

Answer

B

Explanation

A solution of `SO_2` in water reacts with `H_(2)S` precipitating sulphur. Here, `SO_2` act as reducing agent.
`SO_(2)^(+4) + 2H_(2)S^(-2) to 2H_(2)O + overset(0)S`