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If A= {x: x is a multiple of 5} and B] ...

If A= {x: x is a multiple of 5} and B] {x: x is a multiple of 9}. Then, `A nn B` is given by

A

`{3, 6, 9,...}`

B

`{15,30,45,...}`

C

`{5,10,15,20,...}`

D

None of these

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The correct Answer is:
To solve the problem of finding the intersection of sets A and B, where: - \( A = \{ x : x \text{ is a multiple of } 5 \} \) - \( B = \{ x : x \text{ is a multiple of } 9 \} \) we will follow these steps: ### Step 1: Define the sets A and B The set \( A \) consists of all multiples of 5, which can be expressed as: \[ A = \{ 5n : n \in \mathbb{Z} \} \] This means \( A \) includes numbers like \( \ldots, -10, -5, 0, 5, 10, 15, 20, \ldots \). The set \( B \) consists of all multiples of 9, which can be expressed as: \[ B = \{ 9m : m \in \mathbb{Z} \} \] This means \( B \) includes numbers like \( \ldots, -27, -18, -9, 0, 9, 18, 27, \ldots \). ### Step 2: Find the intersection \( A \cap B \) The intersection \( A \cap B \) consists of all elements that are in both sets A and B. To find the common multiples, we need to find the least common multiple (LCM) of 5 and 9. The prime factorization of 5 is \( 5^1 \) and for 9 it is \( 3^2 \). Since 5 and 9 have no common factors, the LCM is: \[ \text{LCM}(5, 9) = 5^1 \times 3^2 = 45 \] ### Step 3: Express the intersection Thus, the intersection \( A \cap B \) can be expressed as: \[ A \cap B = \{ 45k : k \in \mathbb{Z} \} \] This means \( A \cap B \) includes numbers like \( \ldots, -90, -45, 0, 45, 90, \ldots \). ### Final Answer The intersection \( A \cap B \) is: \[ A \cap B = \{ 45k : k \in \mathbb{Z} \} \]
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