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log(a)b = log(b)c = log(c)a, then a, b ...

`log_(a)b = log_(b)c = log_(c)a, ` then a, b and c are such that

A

a=b=c

B

`a=b ne c`

C

`a= c ne b`

D

`b= c ne a`

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The correct Answer is:
A
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