If 10g of ice at 0^(@)C is mixed with 10...

If 10g of ice at `0^(@)C` is mixed with 10g of water at `10^(@)C`, then final temperature t is given by

A

`10 xx 80=10 (10-t)+ 10(t- 0)`

B

`t= 5^(@)C`

C

`t= 0^(@)C`

D

`10 xx 80 + 10 (t- 0)= 10 (10-t)`

Verified by Experts

The correct Answer is:

D

`Q_(1)= 10 xx 1 xx 10= 100` cal
`Q_(2)= 10 xx 80= 800` cal
As `Q_(1) lt Q_(2)`, so final temperature `t= 0^(@)C`

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