Home
Class 12
PHYSICS
1g of ice at 0^(@)C is added to 5g of wa...

1g of ice at `0^(@)C` is added to 5g of water at `10^(@)C`. If the latent heat is 80cal/g, the final temperature of the mixture is

A

`5^(@)C`

B

`0^(@)C`

C

`-5^(@)C`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

`Q_(1)=5 xx 1 xx 10= 50` cal
`Q_(2)= 1 xx 80= 80` cal
`Q_(1) lt Q_(2)` and final temperature `=0^(@)C`
Promotional Banner

Similar Questions

Explore conceptually related problems

One gram of ice at 0^(@)C is added to 5 gram of water at 10^(@)C . If the latent heat of ice be 80 cal/g, then the final temperature of the mixture is -

120 g of ice at 0^(@)C is mixed with 100 g of water at 80^(@)C . Latent heat of fusion is 80 cal/g and specific heat of water is 1 cal/ g-.^(@)C . The final temperature of the mixture is

About 5g of water at 30^(@)C and 5g of ice at -20^(@)C are mixed together in a calorimeter. Calculate final temperature of the mixture. Water equivalent of the calorimeter is negligible. Specific heat of ice =0.5"cal"g^(-1)C^(@)-1) and latent heat of ice =80"cal"g^(-1)

19 g of water at 30^@C and 5 g of ice at -20^@C are mixed together in a calorimeter. What is the final temperature of the mixture? Given specific heat of ice =0.5calg^(-1) (.^(@)C)^(-1) and latent heat of fusion of ice =80calg^(-1)

336 g of ice at 0^@C is mixed with 336 g of water at 80^@C . What is the final temperature of the mixture?

540 g of ice at 0^(@)C is mixed with 540 g of water at 80^(@)C . The final temperature of the mixture is