100g of ice is mixed with 100g of water ...

100g of ice is mixed with 100g of water at `100^(@)C`. What will be the final temperature of the mixture?

A

`10^(@)C`

B

`20^(@)C`

C

`30^(@)C`

D

`40^(@)C`

Verified by Experts

The correct Answer is:

A

Let the final temperature of mixture be t. Then, `100 xx 80 + 100 (t- 0) = 100 xx 1 xx (100-t)` Solving, we get `t = 10^(@)C`

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