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If 0.1% increase in length due to stretc...

If 0.1% increase in length due to stretching occurs, the percentage increase in resistance of wire will be

A

`0.2%`

B

`2%`

C

`1%`

D

`0.1%`

Text Solution

Verified by Experts

The correct Answer is:
A
As `R=(rho l)/(S)` For given wire, `rho` and volume V are constant. Take log and differentiate for small variations.
`R=(rho l)/(("volume"//l))=(rhol^(2))/(("volume"))`
`logR=2log l+log ((rho)/("volume"))`
`(dR)/(R)=(dl)/(l)`
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