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A cell of emf 2 V and internal resistanc...

A cell of emf 2 V and internal resistance `0.1 Omega` is connected with a resistance of `3.9 Omega` The voltage across the cell terminal will be

A

`1.95V`

B

`1.90V`

C

`0.50V`

D

`2.00V`

Text Solution

Verified by Experts

The correct Answer is:
A
As `E=l(R+r) rArr 2=l (3.9+0.1)=4l`
`rArr l=(2)/(4)=(1)/(2)`
From, V=lR
`rArr V=(1)/(2)xx3.9=19.5V`
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