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A wire of resistance R is cut into n equ...

A wire of resistance R is cut into n equal parts. These parts are then connected in parallel. The equivalent resistance of the combination will be

A

nR

B

`(R)/(n)`

C

`(n)/(R)`

D

`(R)/(n^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
Resistance of each segment n such segments are in parallel. Resistance = `R_("eff")`
`(1)/(R_("eff"))=(1)/(R//n)=(1)/(R//n).....` to n terms
`(1)/(R_("eff"))=(n)/(R)+(n)/(R)+.....(n^(2))/(R)`
`R_("eff"")=R//n^(2)=(R)/(n^(2))`
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