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Two particles, each of mass m and charge...

Two particles, each of mass m and charge q are attached to the two ends of a light rigid rod of length 2R. The rod is rotated at constant angular speed about a perpendicular axis passing through its centre. The ratio of the magnitudes of the magnetic moment of the system and its angular momentum about the centre of the rod is

A

`(q)/(m)`

B

`(2q)/(m)`

C

`(q)/(2m)`

D

`(q)/(pim)`

Text Solution

Verified by Experts

The correct Answer is:
C
As `i=2q.(omega)/(2pi)=(qomega)/(pi)`
`:.M=iA=(qomega)/(pi).piR^(2)`
`impliesM=qomegaR^(2)=` Magnetic moment
Now, angles momentnm `" "L=(2R)(mv)=2R.mRomega`
`=2mR^(2)omega" "( :.v=Romega)`
`:.(M)/(L)=(qomegaR^(2))/(2mR^(2)omega)=(q)/(2m)`
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