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In the laboratory, SO2 is prepared by...

In the laboratory, `SO_2` is prepared by

A

dil. H2SO, and sodium sulphide

B

conc. `H_2 SO_4` and sodium sulphide

C

conc. `H_2 SO_4` and copper heated together

D

None of the above

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To prepare sulfur dioxide (SO₂) in the laboratory, we can follow these steps based on the reaction between concentrated sulfuric acid and copper: ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactants needed for this preparation are concentrated sulfuric acid (H₂SO₄) and copper (Cu). 2. **Set Up the Reaction**: - When concentrated sulfuric acid reacts with copper, the reaction can be represented as: \[ \text{Cu} + \text{H}_2\text{SO}_4 \rightarrow \text{CuSO}_4 + \text{H}_2\text{O} + \text{SO}_2 \] - In this reaction, copper (Cu) is oxidized, and sulfuric acid is reduced, leading to the formation of sulfur dioxide (SO₂). 3. **Balance the Reaction**: - The balanced chemical equation is: \[ \text{Cu} + 2 \text{H}_2\text{SO}_4 \rightarrow \text{CuSO}_4 + 2 \text{H}_2\text{O} + \text{SO}_2 \] - Here, we ensure that the number of atoms for each element is equal on both sides of the equation. 4. **Determine the Correct Option**: - From the options provided: - A: Dilute sulfuric acid and sodium sulfite - B: Concentrated sulfuric acid and sodium sulfite - C: Concentrated sulfuric acid and copper heated together - D: None of the above - The correct option is **C**: Concentrated sulfuric acid and copper heated together.

To prepare sulfur dioxide (SO₂) in the laboratory, we can follow these steps based on the reaction between concentrated sulfuric acid and copper: ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactants needed for this preparation are concentrated sulfuric acid (H₂SO₄) and copper (Cu). 2. **Set Up the Reaction**: ...
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  12. SO2 is not a

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  14. Which reduction shows the oxidising nature of SO2?

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  15. In the presence of moisture SO2

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  18. Which of the following gases produces maximum pollution?

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  19. Pure H2 S gas is obtained by action of water on

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  20. By passing H(2)S in acidified KMnO(4) solution we get

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