Sulphur dioxide reacts with `PCl_5` to give

Options

A. sulphuryl chloride
B. thronyl chloride
C. chloro sulphonic acid
D. sulphur trioxide and chlorine

Explanation

To solve the question "Sulphur dioxide reacts with `PCl_5` to give", we will analyze the reaction step by step.

### Step 1: Identify the Reactants
The reactants in this reaction are Sulphur Dioxide (SO₂) and Phosphorus Pentachloride (PCl₅).

### Step 2: Understand the Reaction
When SO₂ reacts with PCl₅, it undergoes a chemical reaction that leads to the formation of new products.

### Step 3: Write the Reaction Equation
The reaction can be represented as:
\[ \text{SO}_2 + \text{PCl}_5 \rightarrow \text{POCl}_3 + \text{SOCl}_2 \]

### Step 4: Identify the Products
From the reaction equation, we can see that the products formed are:
1. Phosphoryl Chloride (POCl₃)
2. Thionyl Chloride (SOCl₂)

### Step 5: Analyze the Options
Now, we need to match our products with the given options:
- Option A: Sulphuryl Chloride
- Option B: Thionyl Chloride
- Option C: Chlorosulphonic Acid
- Option D: Sulphur Trioxide and Chlorine

From our analysis, we see that Thionyl Chloride (SOCl₂) is one of the products formed in the reaction. Thus, the correct answer is:

**Option B: Thionyl Chloride**

### Summary of the Solution
Sulphur dioxide reacts with PCl₅ to form phosphoryl chloride (POCl₃) and thionyl chloride (SOCl₂). The correct answer is Thionyl Chloride.

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