Ethylene reacts with alkaline (Baeyer's reagent) to form

Options

A. oxalic acid
B. acetic acid
C. glycerol
D. glycol

Explanation

To solve the question of what ethylene forms when it reacts with alkaline Baeyer's reagent, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Ethylene**:
- Ethylene is a simple alkene with the molecular formula \( C_2H_4 \) or \( CH_2=CH_2 \).

2. **Understand Baeyer's Reagent**:
- Baeyer's reagent is a dilute solution of potassium permanganate (\( KMnO_4 \)) in an alkaline medium (basic solution). It is used for the oxidation of alkenes.

3. **Reaction Conditions**:
- The reaction occurs in the presence of water and alkaline \( KMnO_4 \). The alkaline medium is crucial as it facilitates the oxidation process.

4. **Oxidation Reaction**:
- When ethylene reacts with alkaline \( KMnO_4 \), it undergoes syn-dihydroxylation, where the double bond in ethylene is converted into a single bond, and two hydroxyl groups (\( -OH \)) are added across the double bond.

5. **Product Formation**:
- The product formed from this reaction is \( CH_2(OH)-CH_2(OH) \), which is known as glycol or ethylene glycol. However, in the context of the question, glycerol is also mentioned, which is a triol (having three hydroxyl groups).

6. **Conclusion**:
- The primary product of the reaction of ethylene with alkaline Baeyer's reagent is **glycerol**.

### Final Answer:
The reaction of ethylene with alkaline Baeyer's reagent forms **glycerol**.

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