Methanolic solution of ethylene di chloride on heating with zinc dust produces

Options

A. 2-butane
B. ethanol
C. butane
D. ethene

Explanation

To solve the question regarding the reaction of methanolic solution of ethylene dichloride with zinc dust upon heating, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are ethylene dichloride (ClCH2CH2Cl) and zinc dust (Zn).
- The methanolic solution indicates that the reaction occurs in the presence of methanol (CH3OH).

2. **Understand the Reaction Type**:
- This reaction is a dehalogenation reaction, where halogen atoms are removed from the compound.
- Zinc dust acts as a reducing agent, facilitating the removal of chlorine atoms from ethylene dichloride.

3. **Write the Reaction**:
- The reaction can be represented as:
\[ \text{ClCH}_2\text{CH}_2\text{Cl} + \text{Zn} \rightarrow \text{C}_2\text{H}_4 + \text{ZnCl}_2 \]
- Here, ethylene dichloride loses two chlorine atoms to form ethene (C2H4).

4. **Identify the Product**:
- The product formed from the reaction is ethene (C2H4).
- The byproduct of the reaction is zinc chloride (ZnCl2).

5. **Conclusion**:
- Therefore, when methanolic solution of ethylene dichloride is heated with zinc dust, the main product formed is ethene.

### Final Answer:
The product formed is **ethene (C2H4)**.

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