Iodination of alkane is carried out in the presence of

Options

A. alcohol
B. `HNO_3` or `HIO_3`
C. any reducing agent
D. benzene

Explanation

To solve the question regarding the iodination of alkanes, we will follow these steps:

### Step-by-step Solution:

1. **Understanding the Process of Iodination of Alkanes**:
- Iodination of alkanes refers to the introduction of iodine into an alkane molecule. This process can be reversible or irreversible depending on the conditions and reagents used.

2. **Identifying the Reagents**:
- The question provides several options: Alcohol, HNO3, HIO3, any reducing agent, or Benzene. We need to determine which of these is suitable for the iodination of alkanes.

3. **Analyzing the Role of HNO3 and HIO3**:
- HNO3 (Nitric Acid) and HIO3 (Iodic Acid) are known to facilitate the iodination process. They help in the formation of iodine (I2) from iodate ions, which is crucial for the iodination reaction.

4. **Reversible vs. Irreversible Reaction**:
- The iodination of alkanes can be reversible if only iodine is used. However, when HNO3 or HIO3 is present, the reaction tends to proceed in the forward direction, leading to the formation of alkyl iodides.

5. **Final Reaction**:
- For example, when methane (CH4) reacts with iodine (I2) in the presence of HNO3 or HIO3, it produces methyl iodide (CH3I) and hydrogen iodide (HI). This reaction is facilitated and made irreversible by the presence of HNO3 or HIO3.

6. **Conclusion**:
- Therefore, the correct answer to the question is that iodination of alkanes is carried out in the presence of HNO3 or HIO3.

### Final Answer:
The iodination of alkane is carried out in the presence of **HNO3 or HIO3**.

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