In the sequence of reactions `CH -= CH + H_2O underset(60^(@)C) overset(H_2SO_4 * HgSO_4) to [A] overset([O]) to [B]`
The compound A and B are

Options

A. acetone and acetic acid respectively
B. acetaldehyde and acetic acid respectively
C. acetaldehyde and ethyl alcohol respectively
D. ethyl alcohol and acetaldehyde

Explanation

To solve the given question step by step, we will analyze the reactions involved and identify the compounds A and B.

### Step 1: Identify the starting compound
The starting compound is **ethene (CH₂=CH₂)**.

### Step 2: Reaction with water
When ethene reacts with water (H₂O) in the presence of sulfuric acid (H₂SO₄) and mercuric sulfate (HgSO₄) at 60°C, it undergoes hydration. According to Markovnikov's rule, the hydrogen atom from water will add to the carbon atom with more hydrogen atoms (the less substituted carbon), and the hydroxyl group (OH) will add to the other carbon atom.

**Reaction:**
\[ \text{CH}_2=CH_2 + H_2O \xrightarrow{H_2SO_4, HgSO_4} \text{CH}_3CHO \]

This results in the formation of **acetaldehyde (CH₃CHO)**, which is compound A.

### Step 3: Oxidation of compound A
Next, we oxidize compound A (acetaldehyde) to form compound B. The oxidation of an aldehyde typically yields a carboxylic acid.

**Oxidation Reaction:**
\[ \text{CH}_3CHO \xrightarrow{[O]} \text{CH}_3COOH \]

This results in the formation of **acetic acid (CH₃COOH)**, which is compound B.

### Summary of Compounds
- Compound A: **Acetaldehyde (CH₃CHO)**
- Compound B: **Acetic Acid (CH₃COOH)**

### Final Answer
The compounds A and B are:
- A = Acetaldehyde (CH₃CHO)
- B = Acetic Acid (CH₃COOH)

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