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Which one of the following reagents dist...

Which one of the following reagents distinguish ethylene from acetylene?

A

Aqueous alkaline `KMnO_4`

B

`Cl_2` dissolved in `C Cl_4`

C

Ammoniacal `Cu_2Cl_2`

D

Conc. `H_2SO_4`

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AI Generated Solution

The correct Answer is:
To distinguish between ethylene (C2H4) and acetylene (C2H2), we can use ammoniacal copper(II) chloride (Cu2Cl2). Here's a step-by-step solution: ### Step 1: Understand the Reactivity of the Compounds - Ethylene (C2H4) is an alkene with a double bond. - Acetylene (C2H2) is an alkyne with a triple bond. - Alkynes generally react differently than alkenes due to the presence of the triple bond. ### Step 2: Identify the Reagent - The reagent in question is ammoniacal copper(II) chloride (Cu2Cl2). This reagent is known to react specifically with alkynes. ### Step 3: Reaction with Acetylene - When acetylene (C2H2) reacts with ammoniacal copper(II) chloride, it forms a complex known as copper acetylide (CuC2H). The reaction can be represented as: \[ \text{C2H2} + \text{Cu2Cl2} \rightarrow \text{CuC2} + \text{NH4Cl} + 2\text{H2O} \] - This reaction indicates that acetylene can be distinguished because it forms a precipitate of copper acetylide. ### Step 4: Reaction with Ethylene - Ethylene (C2H4), on the other hand, does not react with ammoniacal copper(II) chloride. Therefore, no product is formed when ethylene is treated with this reagent. ### Step 5: Conclusion - Since acetylene reacts to form a copper complex while ethylene does not react, ammoniacal copper(II) chloride can be used to distinguish between the two compounds. ### Final Answer - The reagent that can distinguish ethylene from acetylene is **Ammoniacal Cu2Cl2**. ---

To distinguish between ethylene (C2H4) and acetylene (C2H2), we can use ammoniacal copper(II) chloride (Cu2Cl2). Here's a step-by-step solution: ### Step 1: Understand the Reactivity of the Compounds - Ethylene (C2H4) is an alkene with a double bond. - Acetylene (C2H2) is an alkyne with a triple bond. - Alkynes generally react differently than alkenes due to the presence of the triple bond. ### Step 2: Identify the Reagent ...
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