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""(92)^(235)U, ""(92)^(238)U and ""(92)^...

`""_(92)^(235)U, ""_(92)^(238)U` and `""_(92)^(239)U` are

A

isomers

B

isotopes

C

isobars

D

Isotones

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To solve the question regarding the nature of the elements \( _{92}^{235}U, _{92}^{238}U, \) and \( _{92}^{239}U \), we need to analyze the definitions of isomers, isotopes, isobars, and isotones. ### Step-by-Step Solution: 1. **Identify the Atomic Number:** - All three elements \( _{92}^{235}U, _{92}^{238}U, \) and \( _{92}^{239}U \) have the same atomic number, which is 92. This indicates that they are all isotopes of uranium. **Hint:** The atomic number indicates the number of protons in the nucleus and defines the element. 2. **Identify the Mass Numbers:** - The mass numbers for the three isotopes are: - \( _{92}^{235}U \) has a mass number of 235. - \( _{92}^{238}U \) has a mass number of 238. - \( _{92}^{239}U \) has a mass number of 239. - Since the mass numbers are different, this confirms that they are isotopes. **Hint:** The mass number is the sum of protons and neutrons in the nucleus. 3. **Define Isotopes:** - Isotopes are defined as atoms of the same element (same atomic number) that have different mass numbers (different numbers of neutrons). **Hint:** Look for elements with the same atomic number but different mass numbers to identify isotopes. 4. **Conclusion:** - Since \( _{92}^{235}U, _{92}^{238}U, \) and \( _{92}^{239}U \) all have the same atomic number (92) but different mass numbers (235, 238, and 239), they are classified as isotopes. **Final Answer:** The elements \( _{92}^{235}U, _{92}^{238}U, \) and \( _{92}^{239}U \) are **isotopes**.

To solve the question regarding the nature of the elements \( _{92}^{235}U, _{92}^{238}U, \) and \( _{92}^{239}U \), we need to analyze the definitions of isomers, isotopes, isobars, and isotones. ### Step-by-Step Solution: 1. **Identify the Atomic Number:** - All three elements \( _{92}^{235}U, _{92}^{238}U, \) and \( _{92}^{239}U \) have the same atomic number, which is 92. This indicates that they are all isotopes of uranium. **Hint:** The atomic number indicates the number of protons in the nucleus and defines the element. ...
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From the following nuclei select the isotopes and isobars : ""_(92)^(238)U, ""_(90)^(234)Th, ""_(92)^(234)U, ""_(91)^(234)Pa .

Is it possible for ""_(92)U^(238) spontaneously to emit a proton? Given, atomic mass of ""_(92)U^(238), ""_(91)Pa^(237) and ""_(1)H^(1) is 238.05079 u, 237.05115 u and 1.00783 u respectively.

Which of the following pairs represent isotopes and which represent isobars? ""_(92)^(235) U, ""_(92)^(238)U Calculate the difference in the number of neutrons in the isotopic pairs.

The atomic mass of uranium ._(92)^(238)U is 23.058 u , that of throium ._(90)^(234)Th is 234.0436 u and that of an alpha particle ._2^4He is 4.006 u , Determine the energy released when alpha-decay converts ._(92)^(238)U into ._(92)^(238) U . int ._(90)^(234)Th .

Consider two arbitaray decay equation and mark the correct alternative s given below. (i) ._(92)^(230)U rarr n+._(92)^(229)U (ii) ._(92_^(230)U rarr P +._(91)^(229)Pa Given: M(._(92)^(230)U) =230.033927 u,M(._(92)^(229)U)=229.03349 u, m_(n)=1.008665u , M(._(91)^(229)Pa) =229.032089, m_p =1.007825, 1 am u =931.5 MeV .

Fill in the blank ""_(92)U^(235) +""_(0)n^(1) to ? +""_(36)^(92)Kr + 3""_(0)^(1)n

In the transformation of ""_(92)""^(238)U to ""_(92)""^(234)U , if one emission is an alpha particle, what should be the other emission(s)?

How many alpha and beta -particles are emitted in the transformation ""_(92)^(238)U rarr ""_(92)^(234)U

""_(0)n^(1) + ""_(92)U^(235) to ""_(92)U^(236) to .............. + ""_(36)Kr^(89) + 3""_(0)n^(1)

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