On reaction with water, `Al_(4)C_(3)` gives

Options

A. methane
B. ethylene
C. acetylene
D. propene

Explanation

To solve the question regarding the reaction of Aluminium Carbide (Al₄C₃) with water, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant in this case is Aluminium Carbide (Al₄C₃).
- The other reactant is water (H₂O).

2. **Write the Reaction**:
- When Aluminium Carbide reacts with water, it produces methane (CH₄) and Aluminium Hydroxide (Al(OH)₃).
- The unbalanced chemical equation is:
\[ \text{Al}_4\text{C}_3 + \text{H}_2\text{O} \rightarrow \text{CH}_4 + \text{Al(OH)}_3 \]

3. **Balance the Reaction**:
- To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides.
- The balanced equation is:
\[ \text{Al}_4\text{C}_3 + 12 \text{H}_2\text{O} \rightarrow 3 \text{CH}_4 + 4 \text{Al(OH)}_3 \]

4. **Determine the Products**:
- From the balanced equation, we can see that the products formed are methane (CH₄) and Aluminium Hydroxide (Al(OH)₃).

5. **Select the Correct Option**:
- Among the options provided (A: Methane, B: Ethylene, C: Acetylene, D: Propene), the correct product formed is methane (CH₄).

### Final Answer:
- The correct answer is **Option A: Methane**.