The compound, in which oxygen has oxidation state of +2, is

Options

A. `H_2O`
B. `H_2O_2`
C. `OF_2`
D. `KO_2`

Explanation

To determine the compound in which oxygen has an oxidation state of +2, we can analyze the given options: H2O, H2O2, OF2, and KO2.

### Step-by-Step Solution:

1. **Understanding Oxidation States**:
- The oxidation state of an element in a compound indicates the degree of oxidation (loss of electrons) of that element. Oxygen typically has an oxidation state of -2 in most compounds. However, there are exceptions where it can have positive oxidation states.

2. **Analyzing Each Compound**:
- **H2O (Water)**: In water, the oxidation state of oxygen is -2. Each hydrogen has an oxidation state of +1. Therefore, the total oxidation state of oxygen in H2O is -2.
- **H2O2 (Hydrogen Peroxide)**: In hydrogen peroxide, the oxidation state of oxygen is -1. Each hydrogen still has an oxidation state of +1. The total oxidation state of oxygen in H2O2 is -1.
- **OF2 (Oxygen Difluoride)**: In oxygen difluoride, the oxidation state of oxygen is +2. Fluorine is more electronegative than oxygen, so each fluorine has an oxidation state of -1. Therefore, the total oxidation state of oxygen in OF2 is +2.
- **KO2 (Potassium Superoxide)**: In potassium superoxide, the oxidation state of oxygen is -1/2 for the superoxide ion (O2^−). Therefore, the total oxidation state of oxygen in KO2 is not +2.

3. **Conclusion**:
- The only compound among the options where oxygen has an oxidation state of +2 is **OF2 (Oxygen Difluoride)**.

### Final Answer:
The compound in which oxygen has an oxidation state of +2 is **OF2**.