A compound 'A' with formula `C_(3)H_(8)O` possess two structural isomers. On oxidation it produces an acid. Compound A is

Options

A. 1-propanal
B. 2-propanone
C. 1-propanol
D. 2-propanal

Explanation

To solve the question regarding compound 'A' with the formula C₃H₈O, we will follow these steps:

### Step 1: Identify the molecular formula
The given molecular formula is C₃H₈O. This indicates that the compound contains 3 carbon atoms, 8 hydrogen atoms, and 1 oxygen atom.

**Hint:** Look for the number of carbon, hydrogen, and oxygen atoms to understand the possible structures.

### Step 2: Determine the structural isomers
For C₃H₈O, we can draw two structural isomers:
1. **1-Propanol** (where the hydroxyl group -OH is on the terminal carbon):
- Structure: CH₃-CH₂-CH₂OH
2. **2-Propanol** (where the hydroxyl group -OH is on the middle carbon):
- Structure: CH₃-CHOH-CH₃

**Hint:** Structural isomers have the same molecular formula but different arrangements of atoms.

### Step 3: Analyze oxidation reactions
Next, we need to determine which of these compounds can be oxidized to form an acid:
- **1-Propanol** (C₃H₈O) can be oxidized to **propanoic acid** (C₂H₄O₂).
- **2-Propanol** (C₃H₈O) does not oxidize to form an acid; it forms acetone (C₃H₆O) instead.

**Hint:** Consider the oxidation reactions of alcohols to see if they yield acids.

### Step 4: Conclusion
Since only 1-Propanol can be oxidized to produce an acid, we conclude that compound 'A' is **1-Propanol**.

**Final Answer:** Compound A is **1-Propanol** (or Propan-1-ol).