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In a group of children ,each child gives...

In a group of children ,each child gives a gift to every other child ,If the number of gifts is 132 ,then the number of children are

A

11

B

12

C

14

D

None of these

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The correct Answer is:
To solve the problem of how many children are in a group where each child gives a gift to every other child, resulting in a total of 132 gifts, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: Each child gives a gift to every other child. If there are \( n \) children, each child gives gifts to \( n - 1 \) other children. 2. **Setting Up the Equation**: The total number of gifts exchanged can be represented as: \[ \text{Total Gifts} = n \times (n - 1) \] Since each child gives a gift to \( n - 1 \) children, and there are \( n \) children. 3. **Equating to the Given Total**: We know from the problem that the total number of gifts is 132. Therefore, we can set up the equation: \[ n(n - 1) = 132 \] 4. **Rearranging the Equation**: Rearranging gives us: \[ n^2 - n - 132 = 0 \] 5. **Factoring the Quadratic Equation**: We need to factor the quadratic equation \( n^2 - n - 132 = 0 \). We look for two numbers that multiply to \(-132\) and add to \(-1\). The numbers are \( -12 \) and \( 11 \): \[ n^2 - 12n + 11n - 132 = 0 \] This can be factored as: \[ (n - 12)(n + 11) = 0 \] 6. **Finding the Values of \( n \)**: Setting each factor to zero gives us: \[ n - 12 = 0 \quad \text{or} \quad n + 11 = 0 \] Thus, we find: \[ n = 12 \quad \text{or} \quad n = -11 \] 7. **Determining the Valid Solution**: Since the number of children cannot be negative, we discard \( n = -11 \). Therefore, the number of children is: \[ n = 12 \] ### Final Answer: The number of children is **12**.
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