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The value of cos 52^(@) + cos 68^(@) + c...

The value of `cos 52^(@) + cos 68^(@) + cos 172^(@)` is

A

0

B

1

C

2

D

`(1)/(sqrt(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( \cos 52^\circ + \cos 68^\circ + \cos 172^\circ \), we can use the cosine addition formula. Here’s a step-by-step solution: ### Step 1: Group the cosines We can group \( \cos 52^\circ \) and \( \cos 68^\circ \) together and leave \( \cos 172^\circ \) as is. ### Step 2: Apply the cosine addition formula The formula for the sum of cosines is: \[ \cos c + \cos d = 2 \cos\left(\frac{c + d}{2}\right) \cos\left(\frac{c - d}{2}\right) \] Let \( c = 52^\circ \) and \( d = 68^\circ \). ### Step 3: Calculate \( c + d \) and \( c - d \) \[ c + d = 52^\circ + 68^\circ = 120^\circ \] \[ c - d = 52^\circ - 68^\circ = -16^\circ \] ### Step 4: Substitute into the formula Now we substitute into the formula: \[ \cos 52^\circ + \cos 68^\circ = 2 \cos\left(\frac{120^\circ}{2}\right) \cos\left(\frac{-16^\circ}{2}\right) \] This simplifies to: \[ \cos 52^\circ + \cos 68^\circ = 2 \cos(60^\circ) \cos(-8^\circ) \] ### Step 5: Evaluate \( \cos(60^\circ) \) We know that: \[ \cos(60^\circ) = \frac{1}{2} \] Thus, we have: \[ \cos 52^\circ + \cos 68^\circ = 2 \cdot \frac{1}{2} \cdot \cos(-8^\circ) = \cos(-8^\circ) \] ### Step 6: Use the property of cosine Using the property \( \cos(-\theta) = \cos(\theta) \): \[ \cos(-8^\circ) = \cos(8^\circ) \] ### Step 7: Combine with \( \cos 172^\circ \) Now we add \( \cos 172^\circ \): \[ \cos 52^\circ + \cos 68^\circ + \cos 172^\circ = \cos(8^\circ) + \cos(172^\circ) \] ### Step 8: Apply the cosine addition formula again Now we apply the cosine addition formula again: Let \( e = 8^\circ \) and \( f = 172^\circ \): \[ \cos 8^\circ + \cos 172^\circ = 2 \cos\left(\frac{8^\circ + 172^\circ}{2}\right) \cos\left(\frac{8^\circ - 172^\circ}{2}\right) \] Calculating \( e + f \) and \( e - f \): \[ e + f = 180^\circ \] \[ e - f = -164^\circ \] ### Step 9: Substitute into the formula Substituting into the formula gives: \[ \cos 8^\circ + \cos 172^\circ = 2 \cos(90^\circ) \cos(-82^\circ) \] ### Step 10: Evaluate \( \cos(90^\circ) \) Since \( \cos(90^\circ) = 0 \): \[ \cos 8^\circ + \cos 172^\circ = 2 \cdot 0 \cdot \cos(-82^\circ) = 0 \] ### Final Answer Thus, the value of \( \cos 52^\circ + \cos 68^\circ + \cos 172^\circ \) is: \[ \boxed{0} \]
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