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The value of 2 sec^(2) theta - sec^(4) ...

The value of ` 2 sec^(2) theta - sec^(4) theta - 2 cosec^(2)theta + cosec^(4) theta` is

A

`cot^(4) theta - tan^(4) theta`

B

`cot^(4) theta - tan^(2) theta`

C

`cot^(4) theta + tan^(4) theta`

D

`cos 4 theta - tan 4 theta`

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The correct Answer is:
To solve the expression \( 2 \sec^2 \theta - \sec^4 \theta - 2 \csc^2 \theta + \csc^4 \theta \), we can follow these steps: ### Step 1: Rearranging the Expression We start by rearranging the terms for clarity: \[ \csc^4 \theta - 2 \csc^2 \theta - (\sec^4 \theta - 2 \sec^2 \theta) \] ### Step 2: Factoring the Terms Next, we can factor each part: \[ \csc^4 \theta - 2 \csc^2 \theta = (\csc^2 \theta)^2 - 2(\csc^2 \theta) = (\csc^2 \theta - 1)^2 \] \[ \sec^4 \theta - 2 \sec^2 \theta = (\sec^2 \theta)^2 - 2(\sec^2 \theta) = (\sec^2 \theta - 1)^2 \] ### Step 3: Substituting the Identities Using the Pythagorean identities: \[ \csc^2 \theta - 1 = \cot^2 \theta \] \[ \sec^2 \theta - 1 = \tan^2 \theta \] we can substitute these into our expression: \[ (\cot^2 \theta)^2 - (\tan^2 \theta)^2 \] ### Step 4: Applying the Difference of Squares Now, we can use the difference of squares formula \( a^2 - b^2 = (a - b)(a + b) \): \[ \cot^4 \theta - \tan^4 \theta = (\cot^2 \theta - \tan^2 \theta)(\cot^2 \theta + \tan^2 \theta) \] ### Final Result Thus, the final simplified expression is: \[ (\cot^2 \theta - \tan^2 \theta)(\cot^2 \theta + \tan^2 \theta) \] ### Conclusion The value of \( 2 \sec^2 \theta - \sec^4 \theta - 2 \csc^2 \theta + \csc^4 \theta \) simplifies to \( \cot^4 \theta - \tan^4 \theta \). ---
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