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The angle of elevation of the Moon when ...

The angle of elevation of the Moon when the length of the shadow of a pole is equal to its height, is

A

`60^(@)`

B

`45^(@)`

C

`90^(@)`

D

`30^(@)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the angle of elevation of the Moon when the length of the shadow of a pole is equal to its height, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: We have a pole of height \( h \) and the length of its shadow is also \( h \). We need to find the angle of elevation \( \theta \) of the Moon from the tip of the shadow. 2. **Draw a Diagram**: - Draw a vertical line representing the pole of height \( h \). - Draw a horizontal line from the base of the pole to the tip of the shadow, which is also of length \( h \). - The angle of elevation \( \theta \) is formed between the line of sight to the Moon and the horizontal line. 3. **Identify the Right Triangle**: - The height of the pole is the opposite side of the triangle, which is \( h \). - The length of the shadow is the adjacent side of the triangle, which is also \( h \). 4. **Use the Tangent Function**: - The tangent of the angle \( \theta \) is given by the formula: \[ \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{h}{h} = 1 \] 5. **Find the Angle**: - We know that \( \tan(\theta) = 1 \). The angle \( \theta \) for which the tangent is 1 is: \[ \theta = 45^\circ \] 6. **Conclusion**: - Therefore, the angle of elevation of the Moon when the length of the shadow of the pole is equal to its height is \( 45^\circ \). ### Final Answer: The angle of elevation of the Moon is \( 45^\circ \). ---
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