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Sides of two similar triangles are in th...

Sides of two similar triangles are in the ratio 4:9. Areas of these triangles are in the ratio

A

2:3

B

4:9

C

18:16

D

16: 81

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The correct Answer is:
To solve the problem, we need to find the ratio of the areas of two similar triangles given that their sides are in the ratio of 4:9. ### Step-by-step Solution: 1. **Understand the relationship between the sides and areas of similar triangles**: - For two similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides. 2. **Identify the ratio of the sides**: - The sides of the two triangles are given in the ratio 4:9. 3. **Set up the ratio of the areas**: - Let the ratio of the sides be represented as: \[ \text{Ratio of sides} = \frac{4}{9} \] - According to the property mentioned, the ratio of the areas will be: \[ \text{Ratio of areas} = \left(\frac{4}{9}\right)^2 \] 4. **Calculate the square of the ratio**: - Now, calculate the square of the ratio: \[ \left(\frac{4}{9}\right)^2 = \frac{4^2}{9^2} = \frac{16}{81} \] 5. **Conclusion**: - Therefore, the ratio of the areas of the two triangles is: \[ \frac{16}{81} \] ### Final Answer: The areas of the triangles are in the ratio \( \frac{16}{81} \). ---
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ARIHANT PUBLICATION JHARKHAND-MODEL SOLVED PAPER 2016-SECTION C MATHEMATICS
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