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If n coins each of diameter 1.5 cm and t...

If n coins each of diameter 1.5 cm and thickness 0.2 cm are melted and a right circular cylinder of height 10 cm and diameter 5 cm is made, then n is equal to

A

336

B

450

C

512

D

555

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The correct Answer is:
To solve the problem, we need to find the number of coins \( n \) that can be melted to form a right circular cylinder. We will use the formula for the volume of a cylinder and equate the total volume of the coins to the volume of the cylinder. ### Step 1: Calculate the volume of one coin The volume \( V \) of a cylinder is given by the formula: \[ V = \pi r^2 h \] where \( r \) is the radius and \( h \) is the height (or thickness in the case of a coin). For one coin: - Diameter = 1.5 cm, so the radius \( r \) is: \[ r = \frac{1.5}{2} = 0.75 \text{ cm} \] - Thickness \( h \) = 0.2 cm. Now, substituting these values into the volume formula: \[ V_{\text{coin}} = \pi (0.75)^2 (0.2) \] Calculating \( (0.75)^2 \): \[ (0.75)^2 = 0.5625 \] Thus, the volume of one coin is: \[ V_{\text{coin}} = \pi \times 0.5625 \times 0.2 = \pi \times 0.1125 \] ### Step 2: Calculate the volume of \( n \) coins The total volume of \( n \) coins is: \[ V_{\text{total}} = n \times V_{\text{coin}} = n \times \pi \times 0.1125 \] ### Step 3: Calculate the volume of the cylinder Now, we calculate the volume of the cylinder: - Diameter = 5 cm, so the radius \( r \) is: \[ r = \frac{5}{2} = 2.5 \text{ cm} \] - Height \( h \) = 10 cm. Using the volume formula for the cylinder: \[ V_{\text{cylinder}} = \pi (2.5)^2 (10) \] Calculating \( (2.5)^2 \): \[ (2.5)^2 = 6.25 \] Thus, the volume of the cylinder is: \[ V_{\text{cylinder}} = \pi \times 6.25 \times 10 = 62.5\pi \] ### Step 4: Set the volumes equal to each other Since the total volume of the coins equals the volume of the cylinder, we have: \[ n \times \pi \times 0.1125 = 62.5\pi \] Dividing both sides by \( \pi \): \[ n \times 0.1125 = 62.5 \] ### Step 5: Solve for \( n \) Now, we can solve for \( n \): \[ n = \frac{62.5}{0.1125} \] Calculating the right-hand side: \[ n = \frac{625}{1.125} = 555.555\ldots \] Thus, rounding to the nearest whole number, we find: \[ n \approx 556 \] ### Final Answer Therefore, the value of \( n \) is approximately \( 556 \).
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